If y varies directly as x and z, and Y=40 when x =5 andz = 4, find y when x=2 and z = 1 Pls answer it ASAP

When x=2 and z = 1, then the value of y =4.

Step-by-step explanation:

Given: y varies directly as x and z i.e.

     (i) , where k is the proportionality constant.

Put  Y=40 ,x =5 and z = 4, then we get

Required equation:  [Put value of k in (i)]

Now put x=2 and z = 1, then we get

Hence, when x=2 and z = 1, then the value of y =4.

is there any other information given for this problem? this is not enough information.