If f(x)=ax^2+bx+c and f(0)=-4 and f(1)=-2 and f(2)=6, what is the value of A and B and C?

Hello There!!

I'm not a 100% sure this right.

Step-by-step explanation:

f(x)=ax2+bx+c for which f(1)=0, f(-2)=6 and f(2)=-14

0 = a +b +c

6 =4a -2b +c

-14=4a+2b +c

subtract third equation from second to get

20 = -4b and so b=-5

first equation is now 5 = a+c

second is now -4=4a+c

subtract to get -9=3a and so a=-3

equation one now is 0=-3-5+c or c=8 Hope This Helps!!

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.

answer: idk

step-by-step explanation: