A planet rotates on an axis through its poles and 1 revolution takes 1 day 1 day is 24 hours. The distance from the axis to a location the planet 30 degrees north latitude is about 3387.5 miles. Therefore, a location on the planet at 30 degrees north latitude is spinning on a circle of radius 3387.5 miles. Compute the linear speed on the surface of the planet at 30 degrees north latitude.

The velocity is  

Step-by-step explanation:

From the question we are told that

    The period of each revolution is  

    The angle  is

     The radius is  

Generally the linear speed is  mathematically represented as

Where   is the angular speed which is mathematically represented as

substituting values

Thus  

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

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the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9