A simple random sample of 28 Lego sets is obtained and the number of pieces in each set was counted. The sample has a standard deviation of 12.65. Use a 0.05 significance level to test the claim that the number of pieces in a set has a standard deviation different from 11.53.

Step-by-step explanation:

Given that:

A simple random sample n = 28

sample standard deviation S = 12.65

standard deviation = 11.53

Level of significance ∝ = 0.05

The objective is to test the claim that the number of pieces in a set has a standard deviation different from 11.53.

The null hypothesis and the alternative hypothesis can be computed as follows:

Null hypothesis:

Alternative hypothesis:

The test statistics can be determined by using the following formula in order to test if the claim is statistically significant or not.

From the chi-square probabilities table at 0.975 and degree of freedom 27;

= 14.573

From the chi-square probabilities table at 0.975 and degree of freedom 27;

43.195

Decision Rule: To reject the null hypothesis if ; otherwise , do not reject the null hypothesis:

The rejection region is

Conclusion:

We fail to reject the null hypothesis since  test statistic value 32.5002125  lies  between 14.573 and 43.195.

180

step-by-step explanation:

12-2=10

20-2=18

18x10=180

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00