Jackson's rectangular bedroom has an area of 90 sq ft. The area of his bedroom is 9 times that of his rectangular closet. If the closet is 2 ft wide, what is it's length?

5 feet

Step-by-step explanation:

Since Jackson's bedroom is a rectangle, it has dimensions of length times width. Suppose the length is l and the width is w.

The area of a rectangle is given by A = lw, where l is the length and w is the width. Here, we know the area is 90, so:

lw = 90

We also know that this area of 90 square feet is 9 times that of the closet, so suppose the area of the closet is c. Then:

9c = 90

Divide by 9:

c = 90/9 = 10 square feet

So, the area of the closet is 10 square feet. Since the width is 2, we know the length will be:

A = lw

10 = lw

10 = 2 * l

l = 10/2 = 5

The length is thus 5 feet.

~ an aesthetics lover

5 ft

Step-by-step explanation:

If his bedroom is 9 times of his closet, then that means you divide the area of his bedroom by 9.  So, 90 divided by 9=10.  That means the closet has an area of 10 sq. ft.  As we all know, the area is the length times width.  So if the width is 2 ft, then we need to multiply it by a number so it will equal 10.  You can do 10 divided by 2 to find it, which equals 5.  That means the length of the closet is 5 sq. ft.

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.