Two birds start from the same nest and head off in opposite directions. The speed of the first bird is 15mph more than the speed of the second. After 6 hours the two birds are 402 miles apart. Find the speed of each bird?

Step-by-step explanation:

The rate at which distance is increasing between the birds is ...

  r = d/t = (402 mi)/(6 h) = 67 mi/h

This is the sum of the speeds of the two birds, so is 15 mph more than double the speed of the slower bird. That bird's speed is then ...

  (67 -15)/2 = 26 . . . miles per hour

The faster bird is 15 mph faster so is 26+15 = 41 mph.

The slower bird's speed is 26 mph; the faster bird's speed is 41 mph.

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