Mathematics, 12.08.2020 07:01 extraemy

Each student in a school was asked, "What is your favorite color?" The circle graph below shows how they answered Which color was chosen by approximately one fourth of the students?

Approximately what percentage of the students chose purple or green?

Each student in a school was asked, What is your favorite color? The circle graph below shows how

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Answer from: sleepyflower10

a). BLUE color

b). 20%

Step-by-step explanation:

a). "Which color was chosen by approximately one fourth of the students?"

Since one fourth of the students will be represented by one fourth area of the circle given.

That means color of choice represented by the quarter of the circle will be the color liked by one fourth students.

In the figure attached, BLUE color is the choice of one fourth students in the class.

b). Area represented by purple, green and other colors is a quarter of the circle.

If we divide this quarter into five equal sections, then the total of purple and green will be $4\times \frac{1}{5}$ of the the quarter of the circle.

Measure of the angle defined by purple or green sections = $\frac{4}{5}\times 90$

= 72°

Percentage of the students who preferred purple or green = $\frac{72}{360}\times 100$

= 20%

Answer from: Quest

the graph in the attached figure

step-by-step explanation:

we have

$f(x)=2x^{3}-7x^{2} +2x+3$

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

Answer from: Quest

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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