Please Help me!! An 8 foot high camel is loping away from a streetlight. The camel is loping at 12 feet/second. The streetlight is 20 feet high. How fast is the camel’s shadow growing?

Camel's shadow is growing at a rate of 8 ft/sec.

Step-by-step explanation:

Given:

Height of camel = 8 ft

Height of streetlight = 20 ft

Speed of camel = 12 ft / sec

To find:

How fast is the camel's shadow growing = ?

Solution:

First of all, have a look at the image attached for the situation as given in the question statement.

PQ be the streetlight.

AB be the camel.

Camel is loping away from the streetlight.

BT will be the shadow of the camel.

We are given that speed of camel = 12 ft / sec

And we know that Speed is the Rate of change of distance w.r. to time.

i.e. as per the image, we are given:

And we have to find the value of:

(Because s is the shadow length and we have to find the rate of change of shadow's length w.r.to time.)

Here, let us consider the two similar triangles as per the image attached:

Ratio of corresponding sides will be same.

Now, differentiating w.r.to t:

Camel's shadow is growing at a rate of 8 ft/sec.

the answer is 96 degrees

step-by-step explanation:

you have to realize that a line equals 180 degrees

36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls