A display has
6
66 packs of marbles with a total mass of
629
β
g
629...
Mathematics, 04.08.2020 20:01 josie17340
A display has
6
66 packs of marbles with a total mass of
629
β
g
629g629, start text, g, end text. The packaging of each pack has a mass of
2
3
β
g
3
2
gstart fraction, 2, divided by, 3, end fraction, start text, g, end text and each marble has a mass of
4
1
2
β
g
4
2
1
g4, start fraction, 1, divided by, 2, end fraction, start text, g, end text.
Which equation can we use to determine
m
mm, the number of marbles per pack?
Choose 1
Choose 1
(Choice A)
A
6
β
4
1
2
m
+
2
3
=
629
6β
4
2
1
m+
3
2
=6296, dot, 4, start fraction, 1, divided by, 2, end fraction, m, plus, start fraction, 2, divided by, 3, end fraction, equals, 629
(Choice B)
B
6
m
(
4
1
2
+
2
3
)
=
629
6m(4
2
1
+
3
2
)=6296, m, left parenthesis, 4, start fraction, 1, divided by, 2, end fraction, plus, start fraction, 2, divided by, 3, end fraction, right parenthesis, equals, 629
(Choice C)
C
6
m
+
4
1
2
+
2
3
=
629
6m+4
2
1
+
3
2
=6296, m, plus, 4, start fraction, 1, divided by, 2, end fraction, plus, start fraction, 2, divided by, 3, end fraction, equals, 629
(Choice D)
D
6
(
4
1
2
m
+
2
3
)
=
629
6(4
2
1
m+
3
2
)=6296, left parenthesis, 4, start fraction, 1, divided by, 2, end fraction, m, plus, start fraction, 2, divided by, 3, end fraction, right parenthesis, equals, 629
Answers: 1
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