What's the recursive formula of the geometric sequence below? 2, 6, 18, 54, 162, 486,...
O ay = 3; an = an-1 · (2)n-1 for n 2 2
a1 = 2; an = an-1 . (3) for n 2 2
O a1 = 2; an = an-1 • (3)n-1 for n 2 1
ay = 2; an = an-1. (2) for n 2 1

Hey there!

We have an=a1(r^n-1), which is the formula for a geometric sequence.

The common ratio is 3, and 2 is the 1st term.

Thus, we have a1=2(3)^(n-1)

Hope this helps :)

Hey there!

We have an=a1(r^n-1), which is the formula

for a geometric sequence.

The common ratio is 3, and 2 is the 1st

term.

Thus, we have a1=2(3)^(n-1)

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19