A triangular tent has a perimeter of 29 meters. Side a is 3 meters shorter than twice side b and side c is 4 meters longer than side b, Find the length of side b. A)11 meters
B)14 meters
C)9 meters
D)7 meters

D) 7 meters

Step-by-step explanation:

So I would start this off by plugging in the variables into side B. So if we were to plug 7 into B there would be 22 meters left of the perimeter. Therefore meaning 22 between A and C. Now A is 3 meters shorter than TWICE of B. So 7 times 2 is 14 and 14 minus 3 is 11. now we have 11 and 7 which equals 18. 29 minus 18 giving us 11 left. 11 is C. Now it says c is 4 meters longer than B so it 7 plus 4 is 11. And everything adds up. HOPE THIS HELPS.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )