In Isosceles trapezoid ABCD, the longer base, AB, is one and one half times as long as the shorter base, CD. The other two sides, AD and BC, are both 13 cm. long. a. If the perimeter is 76 cm. find the lengths of AB and CD. b. If the height of the trapezoid is 12 cm. find its area. (Hint: Area

otal perimeter = 76cm = AB + BC + CD + AD

AD & BC = 13cm

AB = 1.5*(CD)

Solution:

Since we know AD & BC are both 13cm long, plug those numbers into the perimeter equation

76cm+=+AB+%2B+BC+%2B+CD+%2B+AD Place 13cm in for AD & BC

76cm+=+AB+%2B+13cm+%2B+CD+%2B+13cm Combine like terms

76cm+=+AB+%2B+CD+%2B+26cmSubtract 26cm from both sides

50cm+=+AB+%2B+CD Now it is time to substitute the 1.5*(CD) for AB

50cm+=+1.5%2A%28CD%29+%2B+CD rewrite the equation

50cm+=+2.5%2A%28CD%29 Divide both sides by 2.5

20cm+=+CD

To find AB, plug 20cm in for CD in the equation AB = 1.5*(CD)

AB+=+1.5%2A20cm

AB+=+30cm

c

step-by-step explanation:

i think because what else can be a sample of every member

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi