Can someone explain and tell me how to go about solving this? Will mark brainliest

58 cm

Step-by-step explanation:

Assuming that the squares’s sides are whole numbers, we can find the size of the squares by looking at numbers squared.  We find three that equal 153.

10²=10x10=100

7²=7x7=49

2²=2x2=4

100+49+4=153

Now we look at how they are put together to find the perimeter.

The 2x2 has 3 exposed sides totaling 6.

The 7x7 has a top and bottom of 7, and part of a third side of 7-2=5. 7+7+5=19

The 10x10 has 3 exposed sides of 10, and part of a third side of 10-7=3. 10+10+10+3=33

TOTAL Perimeter = 6+19+33=58 cm

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.