Given ADC ACB and BDC BCA prove a squared + b squared = c squared. Use the two Column proof.

a²  + b²  = c · (e + d) =  c × c = c²

a²  + b²  = c²

Please see attachment

Step-by-step explanation:

Statement,                                                        Reason

ΔADC ~ ΔACB,          Given

AC/AD = BA/AC,        The ratio of corresponding sides of similar triangles

b/e = c/b

b² = c·e

ΔBDC ~ ΔBCA,           Given

BC/BA =  BD/BC,        The ratio of corresponding sides of similar triangles

a/c = d/a        

a² = c·d

a²  + b²   = c·e + c·d

a²  + b²   = c · (e + d)

e + d = c,                       Addition of segment

a²  + b²   = c × c = c²

Therefore, a²  + b²   = c²

step-by-step explanation:

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5