Suppose a researcher compares the means of two independent groups that have the same number of participants in each group. The researcher uses the .05 level of significance and obtains a calculated value of t of 2.11. At least how many participants must be in each group in order to reject the null hypothesis? Options: A. 8 B. 9 C. 11 D. 10

see below

Step-by-step explanation:

it would be c i hope this helps

answer: a

step-by-step explanation:

10.2 units

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions