I will give brainliest In ⊙O, chord XY is 8 cm long and is 10 cm from O. What is the radius ⊙O?

radius ≈ 10.77 cm

Step-by-step explanation:

The segment from the centre O to the chord is a perpendicular bisector.

Thus 2 right triangles are formed with legs 10 cm and 4 cm ( half of XY )

The radius r is the hypotenuse.

Using Pythagoras' identity, then

r² = 4² + 10² = 16 + 100 = 116 ( take the square root of both sides )

r = ≈ 10.77 cm ( to 2 dec. places )

Step-by-step explanation:

perpendicular from center always bisects the chord of circle.

1/2 of chord=1/2×8=4 cm

ian gonna lie that is way to much

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.