Dilate the figure by a scale factor of 0.5 with the origin as the center of dilation. What are the vertices of the image? 1 F '(3, 2.5), G '(5, 0.5), H '(2, 1)
2 F '(2.5, 3), G '(0.5, 5), H '(0.5, 1)
3 F '(−3, −2.5), G '(−5, −0.5), H '(−1, −0.5)
4 F '(3, 2.5), G '(5, 0.5), H '(1, 0.5)

 F '(3, 2.5), G '(5, 0.5), H '(1, 0.5).

From the image the vertices are F(6, 5), G(10, 1), H(2, 1).

We have to dilate the figure by a scale factor of 0.5 with the origin as the center of dilation.

We will multiply the vertices by 0.5.

So the new vertices will be: F '(3, 2.5), G '(5, 0.5), H '(1, 0.5).

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4. F '(3, 2.5), G '(5, 0.5), H '(1, 0.5)

Step-by-step explanation:

The formula for dilations are

where t1 is the scale factor

F has coordinates (6,5) so you can write

Multiply 6 by 0.5 and 5 by 0.5 to get

Next, do G. It has coordinates (10, 1) so you can write

Multiply 10 by 0.5 and 1 by 0.5 to get

Finally, point H has coordinates (2, 1) so you can write

Multiply 2 by 0.5 and 1 by 0.5 to get

Hope this helps. Feel free to ask any follow-up questions.

Have a great day! :)

the answer is 8.64

step-by-step explanation:

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: