A computer tallied the time to work for 200 days and found it reasonable to normal curve. The main Thomas 35 minutes, and the standard deviation with six minutes. For the 200 workday experiment, find the percent of tonic me to work more than 41 minutes.

The probability that computers work more than 41 minutes is 0.15866 or 15.87%.

Step-by-step explanation:

We are given that a computer tallied the time to work for 200 days and found it reasonable to the normal curve. The mean is 35 minutes, and the standard deviation with six minutes.

Let X = the time taken by computer to work for 200 days.

So, X ~ Normal()

The z-score probability distribution for the normal distribution is given by;

                               Z  =    ~ N(0,1)

where, = population mean time = 35 minutes

            = standard deviation = 6 minutes

Now, the probability that computers work more than 41 minutes is given by = P(X > 41 minutes)

      P(X > 41 minutes) = P( > ) = P(Z > 1) = 1 - P(Z 1)

                                                                = 1 - 0.84134 = 0.15866

The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.84134.

3.4 pizzas

step-by-step explanation:

given is a scatter plot showing number of pizzas sold during weeks for different issues of coupon

y represents number of pizzas sold and x number of coupons issued

y is marked verticaly and x horizontally

the trend line is given as

y =3.4x+43

this says that even when no coupon is issued pizzas sold will be 43

and rate of change of pizza sold for 1 unit of coupon = slope = 3.4

i.e. when x increases by 1 unit y increases by 3.4 units

hence for each additional coupon issued 3.4 pizzas more will be sold

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy