Line B passes through the points (5, 10) and (0, 0). What is the slope of the line perpendicular to line B?

The line that is perpendicular to B has a slope of -1/2

Step-by-step explanation:

First find the slope of line B

m = ( y2-y1)/(x2-x1)

    = (10-0)/(5-0)

    = 10/5

    = 2

Lines that are perpendicular have slopes that multiply to -1

m * 2 = -1

m = -1/2

The line that is perpendicular to B has a slope of -1/2

-1/2x

Step-by-step explanation:

Hey there! :)

Well to find the slope of line B we'll use the following formula.

We'll use the points (0,0) and (5,10),

10 - 0 = 10

5 - 0 = 5

Slope = 2x

The slopes of 2 perpendicular lines are reciprocals of each other,

meaning if the slope of line B is 2x then its perpendicular lines slope is -1/2x.

Hope this helps :)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this