Claim: Most adults would erase all of their personal information online if they could. A software firm survey of randomly selected 583 adults showed that 58 % of them would erase all of their personal information online if they could. Find the value of the test statistic.

Test statistic = 3.863

Step-by-step explanation:

We are told that most adults would erase all of their personal information online if they could. Since the word "most" is used, it means more than 50% or 50 percent.

So, p_o = 0.5

Also, we are told that 58 % of them would erase all of their personal information online if they could.

Thus, p^ = 0.58

Number of randomly selected adults; n = 583

The test statistic formula for hypothesis test for proportion is given by:

z = (p^ - p_o)/[√[p_o(1 - p_o)/n]

Plugging in the relevant values, we have;

z = (0.58 - 0.5)/[√[0.5(1 - 0.5)/583]

z = 0.08/0.02070788416

z = 3.863

good job you smart son of a gun you are smarter that einstein. 7

$3,200 x 7.25% = $3,200 x .0725 = $232 interest monthly

$232 monthly x 12 annual = $2, 784

step-by-step explanation: