Suppose a triangle has sides 3, 4, and 6. Which of the following must be true? A: The triangle in question is not a right triangle. B: The triangle in question may or may not be a right triangle. C: The triangle in question is a right triangle.

A: The triangle in question is not a right triangle.

Step-by-step explanation:

If the triangle is a right triangle, then the Pythagorean theorem would hold

a^2 + b^2 = c^2

3^2 + 4^2 = 6^2

9+16 = 36

25 = 36

This is not true so this is not a right triangle

A: The triangle in question is not a right triangle.

Step-by-step explanation:

We can use Pythagorean theorem to check.

a² + b² = c²

3² + 4² = 6²

9 + 16 = 36

25 = 36 (not true)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3