A swimming pool is circular with a 30-ft diameter. The depth is constant along east-west lines and increases linearly from 2 ft at the south end to 7 ft at the north end. Find the volume of water in the pool. (Round your answer to the nearest whole number.) ft3

The volume of water in the pool is; Volume = 3181 ft³

We are given;

Diameter of swimming Pool; d = 30 ft

Thus; radius; r = d/2 = 30/2 = 15 ft

We are told that the depth is constant along east-west lines and increases linearly from 2 ft at the south end to 7 ft at the north end.

Thus, average depth is;

h_avg = (2 + 7)/2

h_avg = 4.5 ft

Formula for area is; A = πr²

Thus;

A = π × 15²

A = 225π

Formula for volume here is;

Volume = Area × depth

Volume = 225π × 4.5

Volume = 3180.86 ft³

Approximating to a whole number gives;

Volume = 3181 ft³

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Volume of water in the pool is 3,182 ft^3

Step-by-step explanation:

In this question, what we want to calculate is the volume of water in the pool.

We proceed as follows;

diameter of pool = 30ft

depth: 2 to 7ft linearly

average depth = (2 + 7)/2 = 9/2 = 4.5 ft

Volume = area * average depth

V = pi * radius^2 * 4.5

where radius = diameter/2 = 30/2 = 15 ft

V = pi * 15^2 * 4.5

V = 22/7 * 225 * 4.5

V = 3,182.14 ft^3

which is 3,182 ft^3 to nearest whole number

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2