If sin theta = 4/5 and cos theta is in quadrant II, then cos theta and tan theta equal what?

In quadrant ll,

cos theta = -3/5

tan theta = -4/3

Step-by-step explanation:

In quadrant ll, only sin is positive, cos and tan are negative

sin theta = opposite/hypotenuse = 4/5

From Pythagoras theorem,

adjacent = sqrt(hyp^2 - opp^2) = sqrt(5^2 - 4^2) = sqrt(25 - 16) = sqrt(9) = 3

cos theta = adjacent/hypotenuse = -3/5

tan theta = opposite/adjacent = -4/3

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x