Set of six numbers has an average of 42. When three of this numbers were removed the remaining three numbers had an average of 72. What was the sum of the removed numbers?

36

Step-by-step explanation:

From the question, we are informed that six numbers has an average of 42. This means that the total number will be equal to:

= 42 × 6

= 252

When three of this numbers were removed the remaining three numbers had an average of 72. The total of this will be:

= 72 × 3

= 216

The sum of the removed numbers will be the difference between the two numbers above. This will be:

= 252 - 216

= 36

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph