Paige launched a ball using a catapult she built. The height of the ball (in meters above the ground) ttt seconds after launch is modeled by h(t)=-5t^2+40th(t)=−5t 2 +40th, left parenthesis, t, right parenthesis, equals, minus, 5, t, squared, plus, 40, t Paige wants to know when the ball will hit the ground. 1) Rewrite the function in a different form (factored or vertex) where the answer appears as a number in the equation. h(t)=h(t)=h, left parenthesis, t, right parenthesis, equals 2) How many seconds after launch does the ball hit the ground? seconds

1) Factor form :

2) 8 second after launch.

Step-by-step explanation:

The height of the ball (in meters above the ground) t seconds after launch is modeled by

To find the time when ball hit the ground, we need to find the factor form of the given function.

When ball hi the ground, then height of the ball from the ground is 0.

Using zero product property, we get

Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.

-5t(t - 8) and it hit 8 seconds after launch.

answer: what in the world is this

step-by-step explanation: