You have a wire that is 50 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The other piece will be bent into the shape of a circle. Let A represent the total area of the square and the circle. What is the circumference of the circle when A is a minimum

88.6647727273 cm²

Step-by-step explanation :

The perimeter of the square =(50/2)

                                               = 25 cm

∴ Side of the square = (25/4)

                                    = 6.25 cm

∴ Area of of the square = (6.25)²

                                        = 39.0625 cm²

The circumference of the circle =(50/2)

                                            = 25 cm

∴ 2πr = 25

⇒ r = 25/(22/7)(2)

Area of the circle = (22/7) { 25/(22/7)2} {25/(22/7)2}

                             = (25×25×7) / (2×2×22)

                             = 4365/88

                             = 49.6022727273 cm²

∴ Total area of the circle and the square =(49.6022727273+39.0625000000)

= 88.6647727273 cm²

Hope it helped

If yes mark BRAINLIEST!

answer:

your answer is: c. 196 7/8 in^3.