2 sin(2theta)

(1 + cos(2theta)) (1 –tan^2theta)

For numerator

2sin(2∅)=2(2sin∅cos∅)

For Denominator

(1+cos(2∅))(1+tan²∅)

=(1+cos(2∅))(sec²∅)

=(1+cos²∅-sin²∅)(sec²∅)

Recall. 1-sin²∅=cos²∅

=2cos²∅(sec²∅)

=2.

Answer is...

2(2sin∅cos∅)/2

=2sin∅cos∅ or sin(2∅)

differnt varibles efect the range

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18