Zahra wants the equation below to have an infinite number of solutions when the missing number is placed in the box. Box (x minus 3) + 2 x = negative (x minus 5) + 4 Which number should she place in the box?

Below

Step-by-step explanation:

Let y be the missing number inside the box. The equation is:

●y( x-3)+2x= -(x-5)+4

● y (x-3) +2x = -x+5+4

● y (x-3) +2x = -x+9

● y (x-3) +2x+x = 9

●y(x-3)+3x =9

● yx-3y+3x= 9

●yx-3y+3x-9=0

●y(x-3) +3(x-3) =0

● (x-3)(y+3) = 0

●x-3=0 or y+3=0

●x=3 or y = -3

●x=3 or -y = 3

Add them together

● x-y = 6

●x=6+y

● y =6-x

So the number we should put in the box is 6-x

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

step-by-step explanation: