Find the exact perimeter (in inches) and area (in square inches) of the segment shown, given that m∠O = 60° and OA = 24 in.

A. Perimeter of segment = 49 in.

B. Area of segment = 52 in².

Step-by-step explanation:

Data obtained from the question include:

Radius (r) = 24 in.

Angle at the centre (θ) = 60°

Perimeter of segment =.?

Area of segment =.?

A. Determination of the perimeter of the segment.

Perimeter of segment = length of arc + length of chord

Length of arc = θ/360 x 2πr

Length of chord = 2r x sine (θ/2)

Pi (π) = 3.14

Length of arc = θ/360 x 2πr

Length of arc = 60/360 x 2 x 3.14 x 24

Lenght of arc = 25.12 in

Length of chord = 2r x sine (θ/2)

Length of chord = 2 x 24 x sine (60/2)

Length of chord = 24 in

Perimeter of segment = length of arc + length of chord

Perimeter of segment = 25.12 + 24

Perimeter of segment = 49.12 ≈ 49 in.

B. Determination of the area of the segment.

Area of segment = Area of sector – Area of triangle.

Area of sector = θ/360 x πr²

Area of triangle = r²/2 sine θ

Area of sector = θ/360 x πr²

Area of sector = 60/360 x 3.14 x 24²

Area of sector = 301.44 in²

Area of triangle = r²/2 sine θ

Area of triangle = 24²/2 x sine 60

Area of triangle = 249.42 in².

Area of segment = Area of sector – Area of triangle.

Area of segment = 301.44 – 249.42

Area of segment = 52.02 ≈ 52 in²

b

step-by-step explanation: