How many more unit tiles must be added to the function f(x)=x2-6x+1 in order to complete the square?

-X

--X

0 0

8 more unit of tiles

Step-by-step explanation:

The function is given as;

f(x) = x² - 6x + 1

Now, we want to add more unit tiles to complete the square.

The given function(f(x)) is of the order 2 due to the highest power of 2 attached to x, but the side of the square will be of the order 1.

Now, Let's make a general order 1 expression ax + b to be the side of the square.

From the function forming the square after adding some p unit tiles, we have;

f(x) + p = (side of square)²

Thus;

x² - 6x + 1 + p = (ax + b)²

x² - 6x + 1 + p = a²x² + 2abx + b²

Comparing both sides of the equation, we have;

a² = 1

2ab = 6

b² = 1 + p

From a² = 1, a = 1

From 2ab = 6,putting 1 for a, we have;

2(1)b = 6

b = 6/2

b = 3

From b² = 1 + p

Putting 3 for b, we have;

3² = 1 + p

9 = 1 + p

9 - 1 = p

p = 8

Thus, 8 more unit of tiles are required to complete the square.

answer: slight chance that it will happen

step-by-step explanation:

answer: a

step-by-step explanation: