Find the roots of the function f(x) = (2^x − 1) - (x2 + 2x − 3) with x ∈ R.

There are no real roots.

Step-by-step explanation:

To find the roots of the function

f(x) = (2^x − 1) - (x2 + 2x − 3) with x ∈ R.

First open the bracket

2^x - 1 - x^2 - 2x + 3 = 0

Rearrange and collect the like terms

2x^2 - x^2 - 2x + 3 - 1= 0

X^2 - 2x + 2 = 0

Factorizing the above equation will be impossible, we can therefore find the root by using completing the square method or the quadratic formula.

X^2 - 2x = - 2

Half of coefficient of x is 1

X^2 - 2x + 1^2 = -2 + 1^2

( x - 1 )^2 = - 1

( x - 1 ) = +/- sqrt(-1)

X = -1 + sqrt (-1) or -1 - sqrt (-1)

The root of the function is therefore

X = -1 + sqrt (-1) or -1 - sqrt (-1)

Since b^2 - 4ac of the function is less than zero, we can therefore conclude that there is no real roots

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.