How many gallons each of 15% alcohol and 5% alcohol should be mixed to obtain 10 gal of 14% alcohol? How many gallons of 15% alcohol should be in the mixture? _ gal

Step-by-step explanation:

each gallon 15% alcohol

and 5% alcohol

*is this question correct?

Step-by-step explanation:

Let x = Gallons of 15% alcohol

   y = gallons of 5% alcohol

x + y = 10 gallons

y = 10 - x

15% of x + 5% of y = 14% of 10 gallons

0.15x + 0.05y = 0.14 * 10

0.15x + 0.05 * ( 10 - x) = 1.4

0.15x + 0.05*10  - x * 0.05 = 1.4

0.15x  + 0.5 - 0.05x = 1.4  

Add like terms

0.10x + 0.5 = 1.4

Subtract 0.5 from both sides

0.10x = 1.4 - 0.5

0.10x = 0.9

Divide both sides by 0.10

x = 0.9/0.1

x = 9

x = 9 gallons

y = 1 gallons

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.