Which point is on the line that passes through point R and is perpendicular to line PQ? (–6, 10) (–4, –8) (0, –1) (2, 4)

(-4, -8)

Step-by-step explanation:

Let the coordinates of common point of the given lines are (x, y),

Thus, the slope of the line passes through the points (a, b) and R(4,2) is,

       2 - b

m1 = ------

        4 - a

Again, the slope of the line passes through two points P(-6,4) and Q(4,-4),

      -4 - 4          -8           -8          -4

m2 = ------  =   --------- = --------- = ---------

        4- (-6)       4 + 6         10        5

= m1 * m2 = -1

  2 - b      -4

= -------   x ---- =  -1

   4 - a      5

        8 - 4b

=     -----------   = 1

        20 - 5a

= 8 - 4b  = 20 - 5a

= 5a - 4b = 12 --------- equation 1

For a = -6   and b = -10

5 x -6  - 4  x  10 = -70 ≠ 12

For a = -4   and b = -8

5 x -4  - 4  x  - 8  = 12 = 12

For a = 0  and b = -1

5 x 0 - 4 x -1 = 4 ≠ 12

For a = 2 and b = 4

5 x 2 - 4 x 4 = -6 ≠ 12

therefore Second is correct

hope it helps and i get the brainliest.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

20%

step-by-step explanation: