An object is launched vertically in the air at 31.85 meters per second from a 9 -meter-tall platform. Using the projectile motion model h left parenthesis t right parenthesis equals negative 4.9 t squared plus v 0 t plus h 0 comma where h(t) is the height of the projectile t seconds after its departure, v 0 is the initial velocity in meters per second, and h 0 is the initial height in meters, determine how long it will take for the object to reach its maximum height. What is the maximum height?

I've been working on this for a few days and i just don't understand, it's due in a few hours. you.the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α.part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part bsuppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i.e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case.part cnow try a numerical problem. what is the direction of the vector w = < -1, 6 > ?