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Mathematics, 29.07.2020 23:01 bri994

Given: RS - tangent to circle k(O) at R, TU - tangent to circle k(O) at T, SU - tangent to circle k(O) at V, OS⊥OU. Prove: RS ∥ TU

Given: RS - tangent to circle k(O) at R, TU - tangent to circle k(O) at T, SU - tangent to circle k

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