What is the slope of the line described by 2x + 3y = 4?

A. 2/3
B. -2/3
C. 3/2
D. 2
E. 3

B) -2/3

Step-by-step explanation:

First turn this equation into slope-intercept form(y = mx + b), where m is the slope.

2x+3y=4

3y=-2x+4

y=-2/3x+4/3

Thus, the slope is -2/3

Hope it helps <3

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

8

step-by-step explanation: