Five drivers were used to test drive two models of cars (A and B). The following table displays the number of miles per gallon for each driver. Driver
Model 1 2 3 4 5
A 30 31 30 27 32
B 36 35 28 31 30

Note that the models of cars are treatments and drivers are blocks. The objective is to test if there is any difference in the mean miles per gallon between the two models of cars? Use a level of significance of 5%. The mean square due treatments is:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x

the answer to this is a. a^2 + b^2 = c^2