The graph for the equation y = negative 2 x + 1 is shown below. On a coordinate plane, a line with negative slope goes through (0, 1) and (1, negative 1). If another equation is graphed so that the system has no solution, which equation could that be? y = negative 2 (x minus one-half) y = negative one-half (4 x + 2) y = negative x + 1 y = negative one-half x + 2 WILL BRAINLIEST

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

maybe i can