A company finds that if they price their product at $ 35, they can sell 225 items of it. For every dollar increase in the price, the number of items sold will decrease by 5. What is the maximum revenue possible in this situation? (Do not use commas when entering the answer) $

What price will guarantee the maximum revenue? $

Maximum revenue = $8000

The price that will guarantee the maximum revenue is $40

Step-by-step explanation:

Given that:

Price of product = $35

Total sale of items = 225

For every dollar increase in the price, the number of items sold will decrease by 5.

The total cost of item sold = 225 ×35

The total cost of item sold = 7875

If c should be the dollar unit in price increment;

Therefore; the cost function is :

For maximum revenue;

0+225-35× 5 -10c = 0

225 - 175  =10c

50 = 10c

c = 50/10

c = 5

Maximum revenue =

Maximum revenue =

Maximum revenue = (35 + 5)(225-25)

Maximum revenue = (40 )(200)

Maximum revenue = $8000

The price that will guarantee the maximum revenue is :

=(35 +c)

= 35 + 5

= $40

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.