In a regular triangle ABC with side 1, two squares MNKL, RKPT are drawn such that points M, L, R are on the side AC (the order of the points on that side is as follows: A, M, L, R, C). Points P, T are on the side BC (the order of the points on that side is as follows: B, P, T, C). And the point N is on the side AB. Find the lengths of the sides of the two squares.

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step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus