Question 1 A 16-ounce bag of sugar is supposed to weigh 16 ounces, but it is acceptable for the weight of the bag to vary as much as 0.4 ounce. Which absolute value inequality can be used to find X, the acceptable
weight of a bag of sugar?

I x - 16ozI ≤ 0.4oz

Step-by-step explanation:

The weight is supposed to be exactly 16 oz.

But we can accept a maximum error of 0.4oz.

Now, if x is the weight of the sugar bag, the error can be calculated as:

E = x - 16oz

if x is larger than 16oz, we have E positive, which means that we have more sugar than 16oz

if x is smaller than 16 oz, we have E negative, which means that we are a little bit short of sugar in the bag.

Now, we know that the maximum error acceptable is 0.4 oz (negative or positive)

So we can write:

-0.4oz ≤ E ≤ 0.4oz

-0.4 ≤ x - 16oz ≤ 0.4oz

Now, if we apply absolute value to the error, we get:

I x - 16ozI ≤ 0.4oz

So the correct option is the fourth one (or the bottom one)

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: