How do you know if an equation has a solution? You have to solve the equation normally. 1) If the equation gives a variable on one side and a number on the other side, the equation has one solution. Ex g = -6 2) If the equation has the same value on both sides of the equation, the equation has infinitely many solutions. Ex, 0 = 0, 5 = 5 3) If the equation has different values on both sides of the equation, the equation has no solutions. Ex, 4 ≠ 10, 4 can never be equal to 10 so there is no solutions. Does anyone get what I’m supposed to answer? If so please help

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.  

srry ask agian

step-by-step explanation:

320ft

step-by-step explanation:

120 divided by 3 equals 40

40 times 4=160

160 times 2=320