Please help find these angle for me plz!

Step-by-step explanation:

In triangle DEF, we have:

Given:

<EDF=56°

<EFD=84°

So, <DEF =180° - 56° - 84° =40° (sum of triangle angles is 180°)

____________

DE is a midsegment of triangle ACB

( since CD=DA(given)=>D is midpoint of [CD]

and BE = EA => E midpoint of [BA] )

According to midsegment Theorem,

. (DE) // (CB) "//"means parallel

. DE = CB/2 = FB =CF

___________

DEBF is a parm /parallelogram.

Proof: (DE) // (FB) [(DE) // (CB)]

AND DE = FB

Then, <EBF = <EDF = 56°

___________

DEFC is parm.

Proof: (DE) // (CF) [(DE) // (CB)]

And DE = CF

Therefore, <DCF = <DEF =40°

___________

In triangle ACB, we have:

<CAB =180 - <ACB - <ABC =180° - 40° - 56° =84° (sum of triangle angles is 180°)

$9.41

step-by-step explanation:

u bout ugly as   a mf

step-by-step explanation: lol