Find the domain and range of
f(x) = 2sinπx
please help me!
how do I graph this function

Step-by-step explanation:

The general form of a sine wave is:

y = A sin(2π/T x − B) + C

where A is the amplitude,

T is the period,

B is the phase (horizontal shift),

and C is the midline (vertical shift).

f(x) = 2 sin(πx)

This is a sine wave with an amplitude of 2, a period of 2, a phase of 0, and a midline of y=0.

To graph, the wave is centered at y=0 and has zeros every half period (x = 0, 1, 2, 3, etc.).  Between the zeros, the wave is either a min or max (±2).

The domain of the function is (-∞, ∞).

The range of the function is [-2, 2].

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.

h= 12 inches

step-by-step explanation: