A shipping container is in the shape of a cube and has a side length of 6ft. It can hold 4 smaller boxes of flour. If the dimensions of the shipping container are tripled, what is the max number of smaller boxes of flour that the shipping box can hold

c. 108

Step-by-step explanation:

Given

Shape of container: Cube

Initial dimension of the container = 6ft by 6ft by 6ft

Initial Number of boxes = 4

Required

Calculate the number of boxes when the dimension is tripled

The first step is to calculate the initial volume of the box;

This implies that the container can contain 4 small boxes when its volume is 216;

Represent this as a ratio;

The next step is to calculate the volume when the dimension is tripled;

Hence;

Let the number of boxes it can contain be represented with x

Similarly, represent this as a ratio

Equate both ratios;

Convert ratios to fractions

Multiply both sides by 5832

Hence, the maximum number of boxes it can contain is 108

i am unable to solve this problem

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1