A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket (write out the full number). y=-16x^2+147x+118 The Maximum Height reached by the rocket is feet.

The Maximum Height reached by the rocket is 456.1 feet

Step-by-step explanation:

In order to calculate the maximum height reached by the rocket we would have to calculate first the derivative of y=-16x^2+147x+118 as follows:

derivative of y=-16x^2+147x+118=y'=dy/dx=d/dx(-16x^2+147x+118)

y'=-32x+147

Therefore, x=147/32

x=4.59375

Therefore, the maximum height reached by the rocket=-16*4.59375^2 + 147*4.59375 + 118

The maximum height reached by the rocket=456.1

The Maximum Height reached by the rocket is 456.1 feet

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: