How do i solve for this help please \sqrt(x+5) = \sqrt(x)+1

x=4

Step-by-step explanation:

sqrt(x+5) = sqrt(x)+1

Square each side

(sqrt(x+5))^2 = (sqrt(x)+1)^2

x+5 = (sqrt(x)+1)^2

Foil

x+5 = (sqrt(x)) ^2 + sqrt(x) + sqrt(x) + 1

x+5 = x + 2 sqrt(x) + 1

Subtract x from each side

5 = 2 sqrt(x) + 1

Subtract 1 from each sdie

4 = 2 sqrt(x)

Square each side

4^2 = (2 sqrt(x))^2

16 = 4 x

Divide by 4

16/4 = 4x/4

4 =x

Check to see if it is extraneous

sqrt(4+5) = sqrt(4)+1

sqrt(9) = sqrt(4) +1

3 = 2+1

3=3

It is a valid solution

Step-by-step explanation:

Take the square on both sides.

Expand brackets.

Subtract 2√x, x, and 5 on both sides.

Cancel negative signs.

Divide both sides by 2.

Square both sides.

Check if the solution in the equation works.

Let

The value of x as 4 works in the equation.

3x + 4y -25 =0 represents the amount of change sianna should recieve