Pls help!! Thank you so much if you help me on this, pls show proof

√468 = 6√13

Step-by-step explanation:

ABCDEF is a regular hexagon of side length 6.

A'B'C'D'E'F' is the reflection of ABCDEF across BC.

The line FE' is the line from F to E'.  It is also the hypotenuse of the right triangle FEE'.  FE = 6, and EE' = 4a, where a is the apothem of the hexagon.

To find the apothem, draw the 30-60-90 triangle formed by the apothem and the radius (essentially 1/12th of the hexagon).

Using properties of a 30-60-90 triangle:

a = (6/2)√3

a = 3√3

4a = 12√3

Using Pythagorean theorem:

x² = (6)² + (12√3)²

x² = 36 + 432

x = √468

x = 6√13

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

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step-by-step explanation: