If y varies jointly with x and y =3 when x=2 and z=4 find y when x=8 and z=12

y=10

Step-by-step explanation:

As you can see, the order when x=2 and z=4, is y=x+1, z=y+1, therefore y was 3.

Then, you can find y when x=8 and z=12 by:

12-8=4 (the difference between z and x)

and then divide 4 by 2 (the number of intervals between x, y, and z)

then get 2 (as the difference between x and y.

The answer is 8+2=10.

Hope this helps!

the solution is h=10 because you add 9 to each side of the equation.

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step-by-step explanation: