WILL GIVE BRAINLIEST find the value of r so that the line passes through the points (10, r) and (4, -3) and has the slope of 4/3

r=9⅓

Step-by-step explanation:

(10,r). (4,-3)

(x¹,y¹) (x²,y²)

gradient=y²-y¹

x²-x¹

4= -3-r

34-10

multiply both sides by 3(4-10)to remove the denominators.

3(4-10)× 4 = -3-r ×3(4-10)

3 4-10

(4-10)×4= (3-r)×3

16-40=9-3r

put the liketerms together

note* signs(- +) change when they cross the equal sign(=)

3r=4+40-16

3r=28

divide both sides by 3

r=28/3.

r=9⅓

hm let me think hm think think hm think yes